Figure 3 Initializing a population of ten strings

Strings                                    1s Count  Prob.

U   1  0  0  0  0  0  0  0  0  0  0  0  0  0   1     10%
W   0  0  1  0  0  0  1  0  0  0  0  0  0  0   2     20%
X   0  1  1  1  0  0  0  0  0  1  1  0  0  1   6     30%
Y   0  0  1  1  0  1  1  0  0  1  1  0  0  0   6     40%
X   1  1  0  1  0  1  0  1  1  0  1  1  0  0   8     50%

String's complement

~U  0  1  1  1  1  1  1  1  1  1  1  1  1  1
~W  1  1  0  1  1  1  0  1  1  1  1  1  1  1
~X  1  0  0  0  1  1  1  1  1  0  0  1  1  0
~Y  1  1  0  0  1  0  0  1  1  0  0  1  1  1
~X  0  0  1  0  1  0  1  0  0  1  0  0  1  1